![]() I was AB so I can't help with remembering the rest.COVID-19 Update: To help students through this crisis, The Princeton Review will continue our "Enroll with Confidence" refund policies. ![]() I got the value of 109/60, which I confirmed with my calculator. was asking where something was increasing (or decreasing, I don't quite remember) (I don't know if that helps to spark your memory)Ĥ.a. ![]() Same problem as the last, could've just left it unsimplified and got full credit, but w/e.Ä£.d. Apparently I can do AP Calculus and get near perfect practice tests but can't do rudimentary math skills (forgot what the damn hell to do with those zeros in long subtraction - I don't think I've ever derped so fucking hard before)). Same reasoning for why I remember my calculator was about to be taken when I realized it had an input function, so I quickly integrated it and had to hand subtract, which I REALLY fucked up. (I know because I fucked up in the simplification, forgetting to divide by the 40 and got something like (9pi/40) + 20pi+200pi, and it's been irking me ever since because the simplification will probably make my answer wrong when I could've left it unsimplified and got it correct).Īnd for 1.c, it was 50000 + 7836 (or w/e something high 7000's and ending with a 6), -8050, and you got like 49786 L. The value for the volume of the funnel was (9pi/40)+5i+50pi, or 2209pi/40. Hope this helped and let me know if i have errors cuz i wrote this purely from memory. Just use dy/dx and d^2y/dx^2 to figure out that you have dy/dx=0 and d^2y/dx^2=-4, so it's concave down and therefore local max.Ĭ) You wanted to find the limit of some random thing, at g(-2)=1 and apply l'hopitals twice using dy/dx and d^2y/dx^2, and you get -1/3.Ä)here you wanted to solve (I FORGOT anyone remember this part)Ī) Taylor series, you get like 1-(x-1)/2+((x-1)^2)/8-((x-1)^3)/24 or somethingÄ«) you get -1 ![]() Looking at the graph, you get it is neither since g'(x)=f(x) doesn't change signsÄ«) g does have a point of inflection at x=4, since g''(4)=f'(4)=undefined, and f changes from concave up to concave down.Ĭ) This one, you have to compute area, and at x=6, you get 8 as max, and x=-2, you get -8 as min.įRQ #4 Volume of cone-ish thing or whateverĪ) Here you wanted to find the radius average value I think. Ok Here are some answers if u wanna check your work!įRQ with the water rate flowing in and outĬ) Take 50000 and subtract (7836 or something - 8050) and you get around 49786.Ä) Use intermediate value theorem and/or monotonic functions to determine that yes, there must be a time t when the rates are equal.Ī) Solve the differential equation get C=6, and then get the x coordinate like 9.1, and from graph, y = -1/2 ish, so position is around (14.3,-1/2)Ä«) Just take the slow dy/dx=dy/dt/dx/dt and get around 0.0502 or somethingĬ) Take the arclength and get something (forgot the ans)Ä) Take the integral from 0 to 2 to find the x coordinate, and use graph to find y, then find distance just use pythagįRQ # 3 g(x) = integral from 2 to x of f(t)Ī) Here you wanna find if g(x) at x=10 was a min, max or none.
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